x=0.02x^2+0.05x+0.04

Solution for x=0.02x^2+0.05x+0.04 equation:

x=0.02x^2+0.05x+0.04

We move all terms to the left:

x-(0.02x^2+0.05x+0.04)=0

We get rid of parentheses

-0.02x^2+x-0.05x-0.04=0

We add all the numbers together, and all the variables

-0.02x^2+0.95x-0.04=0

a = -0.02; b = 0.95; c = -0.04;
Δ = b2-4ac
Δ = 0.952-4·(-0.02)·(-0.04)
Δ = 0.8993
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.95)-\sqrt{0.8993}}{2*-0.02}=\frac{-0.95-\sqrt{0.8993}}{-0.04}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.95)+\sqrt{0.8993}}{2*-0.02}=\frac{-0.95+\sqrt{0.8993}}{-0.04}
$